(4y+3)(8-y)=0

Solution for (4y+3)(8-y)=0 equation:

(4y+3)(8-y)=0

We add all the numbers together, and all the variables

(4y+3)(-1y+8)=0

We multiply parentheses ..

(-4y^2+32y-3y+24)=0

We get rid of parentheses

-4y^2+32y-3y+24=0

We add all the numbers together, and all the variables

-4y^2+29y+24=0

a = -4; b = 29; c = +24;
Δ = b2-4ac
Δ = 292-4·(-4)·24
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-35}{2*-4}=\frac{-64}{-8}
=+8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+35}{2*-4}=\frac{6}{-8}
=-3/4
$