12=(4+d)

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Solution for 12=(4+d) equation: 



12=(4+d)

We move all terms to the left:

12-((4+d))=0

We add all the numbers together, and all the variables

-((d+4))+12=0



We calculate terms in parentheses: -((d+4)), so:

(d+4)

We get rid of parentheses

d+4

Back to the equation:

-(d+4)



We get rid of parentheses

-d-4+12=0

We add all the numbers together, and all the variables

-1d+8=0

We move all terms containing d to the left, all other terms to the right

-d=-8

d=-8/-1

d=+8

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