(4y+23)(7y+23)=0

Solution for (4y+23)(7y+23)=0 equation:

(4y+23)(7y+23)=0

We multiply parentheses ..

(+28y^2+92y+161y+529)=0

We get rid of parentheses

28y^2+92y+161y+529=0

We add all the numbers together, and all the variables

28y^2+253y+529=0

a = 28; b = 253; c = +529;
Δ = b2-4ac
Δ = 2532-4·28·529
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(253)-69}{2*28}=\frac{-322}{56}
=-5+3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(253)+69}{2*28}=\frac{-184}{56}
=-3+2/7
$