4x2+-22x=12

Solution for 4x2+-22x=12 equation:

4x^2+-22x=12

We move all terms to the left:

4x^2+-22x-(12)=0

determiningTheFunctionDomain
4x^2-22x-12+=0

We add all the numbers together, and all the variables

4x^2-22x=0

a = 4; b = -22; c = 0;
Δ = b2-4ac
Δ = -222-4·4·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-22}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+22}{2*4}=\frac{44}{8}
=5+1/2
$