5x2-4x-9=0

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Solution for 5x2-4x-9=0 equation:



5x^2-4x-9=0
a = 5; b = -4; c = -9;
Δ = b2-4ac
Δ = -42-4·5·(-9)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-14}{2*5}=\frac{-10}{10} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+14}{2*5}=\frac{18}{10} =1+4/5 $

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