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(4x-6)(8x+4)=0
We multiply parentheses ..
(+32x^2+16x-48x-24)=0
We get rid of parentheses
32x^2+16x-48x-24=0
We add all the numbers together, and all the variables
32x^2-32x-24=0
a = 32; b = -32; c = -24;
Δ = b2-4ac
Δ = -322-4·32·(-24)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-64}{2*32}=\frac{-32}{64} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+64}{2*32}=\frac{96}{64} =1+1/2 $
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