(4x-13)=(3x+19)

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Solution for (4x-13)=(3x+19) equation: 



(4x-13)=(3x+19)

We move all terms to the left:

(4x-13)-((3x+19))=0

We get rid of parentheses

4x-((3x+19))-13=0



We calculate terms in parentheses: -((3x+19)), so:

(3x+19)

We get rid of parentheses

3x+19

Back to the equation:

-(3x+19)



We get rid of parentheses

4x-3x-19-13=0

We add all the numbers together, and all the variables

x-32=0

We move all terms containing x to the left, all other terms to the right

x=32

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