4(4a+5)=3(3a-7)

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Solution for 4(4a+5)=3(3a-7) equation: 



4(4a+5)=3(3a-7)

We move all terms to the left:

4(4a+5)-(3(3a-7))=0

We multiply parentheses

16a-(3(3a-7))+20=0



We calculate terms in parentheses: -(3(3a-7)), so:

3(3a-7)

We multiply parentheses

9a-21

Back to the equation:

-(9a-21)



We get rid of parentheses

16a-9a+21+20=0

We add all the numbers together, and all the variables

7a+41=0

We move all terms containing a to the left, all other terms to the right

7a=-41

a=-41/7

a=-5+6/7

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