(2x-10)+(3x-20)+3x+5x=360

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Solution for (2x-10)+(3x-20)+3x+5x=360 equation: 



(2x-10)+(3x-20)+3x+5x=360

We move all terms to the left:

(2x-10)+(3x-20)+3x+5x-(360)=0

We add all the numbers together, and all the variables

8x+(2x-10)+(3x-20)-360=0

We get rid of parentheses

8x+2x+3x-10-20-360=0

We add all the numbers together, and all the variables

13x-390=0

We move all terms containing x to the left, all other terms to the right

13x=390

x=390/13

x=30

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