(4x+9)(3x+14)=180

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Solution for (4x+9)(3x+14)=180 equation:



(4x+9)(3x+14)=180
We move all terms to the left:
(4x+9)(3x+14)-(180)=0
We multiply parentheses ..
(+12x^2+56x+27x+126)-180=0
We get rid of parentheses
12x^2+56x+27x+126-180=0
We add all the numbers together, and all the variables
12x^2+83x-54=0
a = 12; b = 83; c = -54;
Δ = b2-4ac
Δ = 832-4·12·(-54)
Δ = 9481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(83)-\sqrt{9481}}{2*12}=\frac{-83-\sqrt{9481}}{24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(83)+\sqrt{9481}}{2*12}=\frac{-83+\sqrt{9481}}{24} $

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