4(x-6)-5(x+2)=3(x-8)-18

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Solution for 4(x-6)-5(x+2)=3(x-8)-18 equation: 



4(x-6)-5(x+2)=3(x-8)-18

We move all terms to the left:

4(x-6)-5(x+2)-(3(x-8)-18)=0

We multiply parentheses

4x-5x-(3(x-8)-18)-24-10=0



We calculate terms in parentheses: -(3(x-8)-18), so:

3(x-8)-18

We multiply parentheses

3x-24-18

We add all the numbers together, and all the variables

3x-42

Back to the equation:

-(3x-42)



We add all the numbers together, and all the variables

-1x-(3x-42)-34=0

We get rid of parentheses

-1x-3x+42-34=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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