6(y-2)=4+2(2y+5)

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Solution for 6(y-2)=4+2(2y+5) equation: 



6(y-2)=4+2(2y+5)

We move all terms to the left:

6(y-2)-(4+2(2y+5))=0

We multiply parentheses

6y-(4+2(2y+5))-12=0



We calculate terms in parentheses: -(4+2(2y+5)), so:

4+2(2y+5)

determiningTheFunctionDomain
2(2y+5)+4

We multiply parentheses

4y+10+4

We add all the numbers together, and all the variables

4y+14

Back to the equation:

-(4y+14)



We get rid of parentheses

6y-4y-14-12=0

We add all the numbers together, and all the variables

2y-26=0

We move all terms containing y to the left, all other terms to the right

2y=26

y=26/2

y=13

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