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(4x+6)(2x+8)=600
We move all terms to the left:
(4x+6)(2x+8)-(600)=0
We multiply parentheses ..
(+8x^2+32x+12x+48)-600=0
We get rid of parentheses
8x^2+32x+12x+48-600=0
We add all the numbers together, and all the variables
8x^2+44x-552=0
a = 8; b = 44; c = -552;
Δ = b2-4ac
Δ = 442-4·8·(-552)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-140}{2*8}=\frac{-184}{16} =-11+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+140}{2*8}=\frac{96}{16} =6 $
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