3(y+2)+6y=15

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Solution for 3(y+2)+6y=15 equation: 



3(y+2)+6y=15

We move all terms to the left:

3(y+2)+6y-(15)=0

We add all the numbers together, and all the variables

6y+3(y+2)-15=0

We multiply parentheses

6y+3y+6-15=0

We add all the numbers together, and all the variables

9y-9=0

We move all terms containing y to the left, all other terms to the right

9y=9

y=9/9

y=1

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