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(4x+5)-6=12x-(x+4)-(3x+7)
We move all terms to the left:
(4x+5)-6-(12x-(x+4)-(3x+7))=0
We get rid of parentheses
4x-(12x-(x+4)-(3x+7))+5-6=0
We calculate terms in parentheses: -(12x-(x+4)-(3x+7)), so:We add all the numbers together, and all the variables
12x-(x+4)-(3x+7)
We get rid of parentheses
12x-x-3x-4-7
We add all the numbers together, and all the variables
8x-11
Back to the equation:
-(8x-11)
4x-(8x-11)-1=0
We get rid of parentheses
4x-8x+11-1=0
We add all the numbers together, and all the variables
-4x+10=0
We move all terms containing x to the left, all other terms to the right
-4x=-10
x=-10/-4
x=2+1/2
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