If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+8x=0
a = 12; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·12·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*12}=\frac{-16}{24} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*12}=\frac{0}{24} =0 $
| 13/5^5x-10=1/6^5x-10 | | Y=65x+125 | | 2x+3(-x+1)=5 | | 4n+7n=123 | | 2x-3+x=-5+2x | | 2/27=x/54 | | 125=x(2x-7) | | 2/27=x/36 | | 2/27=x/18 | | -x+1=1/4*x-1.5 | | -x+1=1/4x-1.5 | | 7(2x+1)=14 | | 9/x=63/70 | | 5x+3=−17 | | (x-7)*(5-x+2x²)=0 | | 4(x-2)=4-10 | | 3x-4-6x=3x-4+6x | | -100000=20(35000-x) | | 10^6x=19 | | 35000=35000(21-x) | | 2+3(x-4)-2(x-5)=0.3 | | 3n+2(n+4=68 | | x+10=0.3+10 | | -6x(5-7)+2x=-4+11-6x | | 2x+14÷3x+6=4 | | (2x-1)(x-3)-5(x+4)=x+2)(2×+1) | | 2(x-4)-8=-20 | | 2(x-5)=3(x+6)+2x | | 2(4x-1)=4x-46 | | -3x+29=2x+19 | | 12x+17=5x-25 | | 2x^+3=0 |