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125=x(2x-7)
We move all terms to the left:
125-(x(2x-7))=0
We calculate terms in parentheses: -(x(2x-7)), so:We get rid of parentheses
x(2x-7)
We multiply parentheses
2x^2-7x
Back to the equation:
-(2x^2-7x)
-2x^2+7x+125=0
a = -2; b = 7; c = +125;
Δ = b2-4ac
Δ = 72-4·(-2)·125
Δ = 1049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1049}}{2*-2}=\frac{-7-\sqrt{1049}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1049}}{2*-2}=\frac{-7+\sqrt{1049}}{-4} $
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