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(4x+46)(3x)=4x=46
We move all terms to the left:
(4x+46)(3x)-(4x)=0
We add all the numbers together, and all the variables
-4x+(4x+46)3x=0
We multiply parentheses
12x^2-4x+138x=0
We add all the numbers together, and all the variables
12x^2+134x=0
a = 12; b = 134; c = 0;
Δ = b2-4ac
Δ = 1342-4·12·0
Δ = 17956
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{17956}=134$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(134)-134}{2*12}=\frac{-268}{24} =-11+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(134)+134}{2*12}=\frac{0}{24} =0 $
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