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(4x+2)(3x-15)=18
We move all terms to the left:
(4x+2)(3x-15)-(18)=0
We multiply parentheses ..
(+12x^2-60x+6x-30)-18=0
We get rid of parentheses
12x^2-60x+6x-30-18=0
We add all the numbers together, and all the variables
12x^2-54x-48=0
a = 12; b = -54; c = -48;
Δ = b2-4ac
Δ = -542-4·12·(-48)
Δ = 5220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5220}=\sqrt{36*145}=\sqrt{36}*\sqrt{145}=6\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-6\sqrt{145}}{2*12}=\frac{54-6\sqrt{145}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+6\sqrt{145}}{2*12}=\frac{54+6\sqrt{145}}{24} $
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