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(6-x)(5-x)=0
We add all the numbers together, and all the variables
(-1x+6)(-1x+5)=0
We multiply parentheses ..
(+x^2-5x-6x+30)=0
We get rid of parentheses
x^2-5x-6x+30=0
We add all the numbers together, and all the variables
x^2-11x+30=0
a = 1; b = -11; c = +30;
Δ = b2-4ac
Δ = -112-4·1·30
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*1}=\frac{10}{2} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*1}=\frac{12}{2} =6 $
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