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2.1x^2+9x=4
We move all terms to the left:
2.1x^2+9x-(4)=0
a = 2.1; b = 9; c = -4;
Δ = b2-4ac
Δ = 92-4·2.1·(-4)
Δ = 114.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{114.6}}{2*2.1}=\frac{-9-\sqrt{114.6}}{4.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{114.6}}{2*2.1}=\frac{-9+\sqrt{114.6}}{4.2} $
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