(4x+12)+(80-x)=180

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Solution for (4x+12)+(80-x)=180 equation: 



(4x+12)+(80-x)=180

We move all terms to the left:

(4x+12)+(80-x)-(180)=0

We add all the numbers together, and all the variables

(4x+12)+(-1x+80)-180=0

We get rid of parentheses

4x-1x+12+80-180=0

We add all the numbers together, and all the variables

3x-88=0

We move all terms containing x to the left, all other terms to the right

3x=88

x=88/3

x=29+1/3

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