2(x+4)+3(x-1)=7(x-3)

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Solution for 2(x+4)+3(x-1)=7(x-3) equation: 



2(x+4)+3(x-1)=7(x-3)

We move all terms to the left:

2(x+4)+3(x-1)-(7(x-3))=0

We multiply parentheses

2x+3x-(7(x-3))+8-3=0



We calculate terms in parentheses: -(7(x-3)), so:

7(x-3)

We multiply parentheses

7x-21

Back to the equation:

-(7x-21)



We add all the numbers together, and all the variables

5x-(7x-21)+5=0

We get rid of parentheses

5x-7x+21+5=0

We add all the numbers together, and all the variables

-2x+26=0

We move all terms containing x to the left, all other terms to the right

-2x=-26

x=-26/-2

x=+13

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