1/3(9x+3)=36+1

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Solution for 1/3(9x+3)=36+1 equation: 



1/3(9x+3)=36+1

We move all terms to the left:

1/3(9x+3)-(36+1)=0



Domain of the equation: 3(9x+3)!=0

x∈R



We add all the numbers together, and all the variables

1/3(9x+3)-37=0

We multiply all the terms by the denominator


-37*3(9x+3)+1=0

Wy multiply elements

-111x(9+1=0

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