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(4x+10)-(3x+-5=)
We move all terms to the left:
(4x+10)-(3x+-5-())=0
We use the square of the difference formula
(4x+10)-(3x-5-())=0
We get rid of parentheses
4x-(3x-5-())+10=0
We calculate terms in parentheses: -(3x-5-()), so:We add all the numbers together, and all the variables
3x-5-()
We add all the numbers together, and all the variables
3x
Back to the equation:
-(3x)
x+10=0
We move all terms containing x to the left, all other terms to the right
x=-10
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