7(t+3)-2=(t-2)+5

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Solution for 7(t+3)-2=(t-2)+5 equation: 



7(t+3)-2=(t-2)+5

We move all terms to the left:

7(t+3)-2-((t-2)+5)=0

We multiply parentheses

7t-((t-2)+5)+21-2=0



We calculate terms in parentheses: -((t-2)+5), so:

(t-2)+5

We get rid of parentheses

t-2+5

We add all the numbers together, and all the variables

t+3

Back to the equation:

-(t+3)



We add all the numbers together, and all the variables

7t-(t+3)+19=0

We get rid of parentheses

7t-t-3+19=0

We add all the numbers together, and all the variables

6t+16=0

We move all terms containing t to the left, all other terms to the right

6t=-16

t=-16/6

t=-2+2/3

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