(5(y-4))/3=2y-5

Solution for (5(y-4))/3=2y-5 equation:

(5(y-4))/3=2y-5

We move all terms to the left:

(5(y-4))/3-(2y-5)=0

We get rid of parentheses

(5(y-4))/3-2y+5=0

We multiply all the terms by the denominator


(5(y-4))-2y*3+5*3=0


We calculate terms in parentheses: +(5(y-4)), so:

5(y-4)

We multiply parentheses

5y-20

Back to the equation:

+(5y-20)


We add all the numbers together, and all the variables

(5y-20)-2y*3+15=0

Wy multiply elements

(5y-20)-6y+15=0

We get rid of parentheses

5y-6y-20+15=0

We add all the numbers together, and all the variables

-1y-5=0

We move all terms containing y to the left, all other terms to the right

-y=5

y=5/-1

y=-5