(4x+1)=(7x-35)

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Solution for (4x+1)=(7x-35) equation: 



(4x+1)=(7x-35)

We move all terms to the left:

(4x+1)-((7x-35))=0

We get rid of parentheses

4x-((7x-35))+1=0



We calculate terms in parentheses: -((7x-35)), so:

(7x-35)

We get rid of parentheses

7x-35

Back to the equation:

-(7x-35)



We get rid of parentheses

4x-7x+35+1=0

We add all the numbers together, and all the variables

-3x+36=0

We move all terms containing x to the left, all other terms to the right

-3x=-36

x=-36/-3

x=+12

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