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5x(1-x)=x-5
We move all terms to the left:
5x(1-x)-(x-5)=0
We add all the numbers together, and all the variables
5x(-1x+1)-(x-5)=0
We multiply parentheses
-5x^2+5x-(x-5)=0
We get rid of parentheses
-5x^2+5x-x+5=0
We add all the numbers together, and all the variables
-5x^2+4x+5=0
a = -5; b = 4; c = +5;
Δ = b2-4ac
Δ = 42-4·(-5)·5
Δ = 116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{116}=\sqrt{4*29}=\sqrt{4}*\sqrt{29}=2\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{29}}{2*-5}=\frac{-4-2\sqrt{29}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{29}}{2*-5}=\frac{-4+2\sqrt{29}}{-10} $
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