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3(2x-5)=5(2x+2)
We move all terms to the left:
3(2x-5)-(5(2x+2))=0
We multiply parentheses
6x-(5(2x+2))-15=0
We calculate terms in parentheses: -(5(2x+2)), so:We get rid of parentheses
5(2x+2)
We multiply parentheses
10x+10
Back to the equation:
-(10x+10)
6x-10x-10-15=0
We add all the numbers together, and all the variables
-4x-25=0
We move all terms containing x to the left, all other terms to the right
-4x=25
x=25/-4
x=-6+1/4
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