(4w+8)+(4w+4)=(2w+11)

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Solution for (4w+8)+(4w+4)=(2w+11) equation: 



(4w+8)+(4w+4)=(2w+11)

We move all terms to the left:

(4w+8)+(4w+4)-((2w+11))=0

We get rid of parentheses

4w+4w-((2w+11))+8+4=0



We calculate terms in parentheses: -((2w+11)), so:

(2w+11)

We get rid of parentheses

2w+11

Back to the equation:

-(2w+11)



We add all the numbers together, and all the variables

8w-(2w+11)+12=0

We get rid of parentheses

8w-2w-11+12=0

We add all the numbers together, and all the variables

6w+1=0

We move all terms containing w to the left, all other terms to the right

6w=-1

w=-1/6

w=-1/6

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