(4m+4)(3m-6)=180

Solution for (4m+4)(3m-6)=180 equation:

(4m+4)(3m-6)=180

We move all terms to the left:

(4m+4)(3m-6)-(180)=0

We multiply parentheses ..

(+12m^2-24m+12m-24)-180=0

We get rid of parentheses

12m^2-24m+12m-24-180=0

We add all the numbers together, and all the variables

12m^2-12m-204=0

a = 12; b = -12; c = -204;
Δ = b2-4ac
Δ = -122-4·12·(-204)
Δ = 9936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9936}=\sqrt{144*69}=\sqrt{144}*\sqrt{69}=12\sqrt{69}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{69}}{2*12}=\frac{12-12\sqrt{69}}{24}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{69}}{2*12}=\frac{12+12\sqrt{69}}{24}
$