(2y-1)-5(y-3)+6(3y-4)=83

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Solution for (2y-1)-5(y-3)+6(3y-4)=83 equation: 



(2y-1)-5(y-3)+6(3y-4)=83

We move all terms to the left:

(2y-1)-5(y-3)+6(3y-4)-(83)=0

We multiply parentheses

(2y-1)-5y+18y+15-24-83=0

We get rid of parentheses

2y-5y+18y-1+15-24-83=0

We add all the numbers together, and all the variables

15y-93=0

We move all terms containing y to the left, all other terms to the right

15y=93

y=93/15

y=6+1/5

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