(10x+3)(10x-3)=0

Solution for (10x+3)(10x-3)=0 equation:

(10x+3)(10x-3)=0

We use the square of the difference formula

100x^2-9=0

a = 100; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·100·(-9)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*100}=\frac{-60}{200}
=-3/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*100}=\frac{60}{200}
=3/10
$