(47+3x)+(4x+10)=90

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Solution for (47+3x)+(4x+10)=90 equation: 



(47+3x)+(4x+10)=90

We move all terms to the left:

(47+3x)+(4x+10)-(90)=0

We add all the numbers together, and all the variables

(3x+47)+(4x+10)-90=0

We get rid of parentheses

3x+4x+47+10-90=0

We add all the numbers together, and all the variables

7x-33=0

We move all terms containing x to the left, all other terms to the right

7x=33

x=33/7

x=4+5/7

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