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(x/3)+(-2)=6
We move all terms to the left:
(x/3)+(-2)-(6)=0
determiningTheFunctionDomain (x/3)-6+(-2)=0
We add all the numbers together, and all the variables
(+x/3)-6+(-2)=0
We add all the numbers together, and all the variables
(+x/3)-8=0
We get rid of parentheses
x/3-8=0
We multiply all the terms by the denominator
x-8*3=0
We add all the numbers together, and all the variables
x-24=0
We move all terms containing x to the left, all other terms to the right
x=24
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