(4/z-1)-(5/z+2)=3/2

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Solution for (4/z-1)-(5/z+2)=3/2 equation: 



(4/z-1)-(5/z+2)=3/2

We move all terms to the left:

(4/z-1)-(5/z+2)-(3/2)=0



Domain of the equation: z-1)!=0

z∈R





Domain of the equation: z+2)!=0

z∈R



We add all the numbers together, and all the variables

(4/z-1)-(5/z+2)-(+3/2)=0

We get rid of parentheses

4/z-5/z-1-2-3/2=0

We calculate fractions

There is no solution for this equation

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