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2a+4(a-1)=1+3(2a+1)=
We move all terms to the left:
2a+4(a-1)-(1+3(2a+1))=0
We multiply parentheses
2a+4a-(1+3(2a+1))-4=0
We calculate terms in parentheses: -(1+3(2a+1)), so:We add all the numbers together, and all the variables
1+3(2a+1)
determiningTheFunctionDomain 3(2a+1)+1
We multiply parentheses
6a+3+1
We add all the numbers together, and all the variables
6a+4
Back to the equation:
-(6a+4)
6a-(6a+4)-4=0
We get rid of parentheses
6a-6a-4-4=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation
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