4y+8(y-1)=2+6(2y+10)=

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Solution for 4y+8(y-1)=2+6(2y+10)= equation: 



4y+8(y-1)=2+6(2y+10)=

We move all terms to the left:

4y+8(y-1)-(2+6(2y+10))=0

We multiply parentheses

4y+8y-(2+6(2y+10))-8=0



We calculate terms in parentheses: -(2+6(2y+10)), so:

2+6(2y+10)

determiningTheFunctionDomain
6(2y+10)+2

We multiply parentheses

12y+60+2

We add all the numbers together, and all the variables

12y+62

Back to the equation:

-(12y+62)



We add all the numbers together, and all the variables

12y-(12y+62)-8=0

We get rid of parentheses

12y-12y-62-8=0

We add all the numbers together, and all the variables

-70!=0

There is no solution for this equation

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