(4/u-1)+(6/3u+1)=(15/3u+1)

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Solution for (4/u-1)+(6/3u+1)=(15/3u+1) equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

(6/3)*u+4/u-1+1 = (15/3)*u+1 // - (15/3)*u+1

(6/3)*u-((15/3)*u)+4/u-1-1+1 = 0

(6/3)*u-5*u+4/u-1-1+1 = 0

4*u^-1-3*u^1-1*u^0 = 0

(4*u^0-3*u^2-1*u^1)/(u^1) = 0 // * u^2

u^1*(4*u^0-3*u^2-1*u^1) = 0

u^1

4-3*u^2-u = 0

4-3*u^2-u = 0

DELTA = (-1)^2-(-3*4*4)

DELTA = 49

DELTA > 0

u = (49^(1/2)+1)/(-3*2) or u = (1-49^(1/2))/(-3*2)

u = -4/3 or u = 1

u in { -4/3, 1} 

u in { -4/3, 1 }

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