(4/(u-1))+(6/(3u+1))=(15/(3u+1))

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Solution for (4/(u-1))+(6/(3u+1))=(15/(3u+1)) equation: 


D( u )

3*u+1 = 0

u-1 = 0

3*u+1 = 0

3*u+1 = 0

3*u+1 = 0 // - 1

3*u = -1 // : 3

u = -1/3

u-1 = 0

u-1 = 0

u-1 = 0 // + 1

u = 1

u in (-oo:-1/3) U (-1/3:1) U (1:+oo)

4/(u-1)+6/(3*u+1) = 15/(3*u+1) // - 15/(3*u+1)

4/(u-1)+6/(3*u+1)-(15/(3*u+1)) = 0

4/(u-1)+6/(3*u+1)-15*(3*u+1)^-1 = 0

4/(u-1)+6/(3*u+1)-15/(3*u+1) = 0

(4*(3*u+1))/((u-1)*(3*u+1))+(6*(u-1))/((u-1)*(3*u+1))+(-15*(u-1))/((u-1)*(3*u+1)) = 0

4*(3*u+1)+6*(u-1)-15*(u-1) = 0

18*u-15*u-2+15 = 0

3*u+13 = 0

(3*u+13)/((u-1)*(3*u+1)) = 0

(3*u+13)/((u-1)*(3*u+1)) = 0 // * (u-1)*(3*u+1)

3*u+13 = 0

3*u+13 = 0 // - 13

3*u = -13 // : 3

u = -13/3

u = -13/3

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