20/(4/5)=100/n

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Solution for 20/(4/5)=100/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

20/(4/5) = 100/n // - 100/n

20/(4/5)-(100/n) = 0

20/(4/5)-100*n^-1 = 0

-100*n^-1 = -25 // : -100

n^-1 = 1/4

-1 < 0

1/(n^1) = 1/4 // * n^1

1 = 1/4*n^1 // : 1/4

4 = n^1

n = 4

n = 4

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