(4/7p)-6=(2/7p)+12

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Solution for (4/7p)-6=(2/7p)+12 equation: 



(4/7p)-6=(2/7p)+12

We move all terms to the left:

(4/7p)-6-((2/7p)+12)=0



Domain of the equation: 7p)!=0

p!=0/1

p!=0

p∈R





Domain of the equation: 7p)+12)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

(+4/7p)-((+2/7p)+12)-6=0

We get rid of parentheses

4/7p-((+2/7p)+12)-6=0

We calculate fractions


28p/49p^2+(-((+2*7p)/49p^2-6=0

We calculate fractions

We do not support eppression: p^4

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