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(2/5)x+15=2x-8
We move all terms to the left:
(2/5)x+15-(2x-8)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/5)x-(2x-8)+15=0
We multiply parentheses
2x^2-(2x-8)+15=0
We get rid of parentheses
2x^2-2x+8+15=0
We add all the numbers together, and all the variables
2x^2-2x+23=0
a = 2; b = -2; c = +23;
Δ = b2-4ac
Δ = -22-4·2·23
Δ = -180
Delta is less than zero, so there is no solution for the equation
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