(4/5)+(2/15)x=(2/3)x+4

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Solution for (4/5)+(2/15)x=(2/3)x+4 equation: 



(4/5)+(2/15)x=(2/3)x+4

We move all terms to the left:

(4/5)+(2/15)x-((2/3)x+4)=0



Domain of the equation: 15)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3)x+4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/15)x-((+2/3)x+4)+(+4/5)=0

We multiply parentheses

2x^2-((+2/3)x+4)+(+4/5)=0

We get rid of parentheses

2x^2-((+2/3)x+4)+4/5=0

We calculate fractions


2x^2+()/3x+4)*5)+12x/3x+4)*5)=0

We calculate fractions


2x^2+(()*3x)/9x^2+4*5)+12x*3x)/9x^2=0

We multiply all the terms by the denominator


2x^2*9x^2+(()*3x)+4*5)+12x*3x)=0



We calculate terms in parentheses: +(()*3x), so:

()*3x



Wy multiply elements

18x^4+60x^2+(()*3x)=0



We calculate terms in parentheses: +(()*3x), so:

()*3x



We do not support expression: x^4

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