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4/5+2/15x=2/3x+4
We move all terms to the left:
4/5+2/15x-(2/3x+4)=0
Domain of the equation: 15x!=0
x!=0/15
x!=0
x∈R
Domain of the equation: 3x+4)!=0We get rid of parentheses
x∈R
2/15x-2/3x-4+4/5=0
We calculate fractions
540x^2/1125x^2+150x/1125x^2+(-750x)/1125x^2-4=0
We multiply all the terms by the denominator
540x^2+150x+(-750x)-4*1125x^2=0
Wy multiply elements
540x^2-4500x^2+150x+(-750x)=0
We get rid of parentheses
540x^2-4500x^2+150x-750x=0
We add all the numbers together, and all the variables
-3960x^2-600x=0
a = -3960; b = -600; c = 0;
Δ = b2-4ac
Δ = -6002-4·(-3960)·0
Δ = 360000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{360000}=600$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-600}{2*-3960}=\frac{0}{-7920} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+600}{2*-3960}=\frac{1200}{-7920} =-5/33 $
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