(28x-2)+(10x+30)=180

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Solution for (28x-2)+(10x+30)=180 equation: 



(28x-2)+(10x+30)=180

We move all terms to the left:

(28x-2)+(10x+30)-(180)=0

We get rid of parentheses

28x+10x-2+30-180=0

We add all the numbers together, and all the variables

38x-152=0

We move all terms containing x to the left, all other terms to the right

38x=152

x=152/38

x=4

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