(4/5)+(1/4)t=(3/5)

Solution for (4/5)+(1/4)t=(3/5) equation:

(4/5)+(1/4)t=(3/5)

We move all terms to the left:

(4/5)+(1/4)t-((3/5))=0


Domain of the equation: 4)t!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

(+1/4)t+(+4/5)-((+3/5))=0

We multiply parentheses

t^2+(+4/5)-((+3/5))=0

We get rid of parentheses

t^2+4/5-((+3/5))=0

We calculate fractions


t^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{2}=0$