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120=3x+5(1+4x)
We move all terms to the left:
120-(3x+5(1+4x))=0
We add all the numbers together, and all the variables
-(3x+5(4x+1))+120=0
We calculate terms in parentheses: -(3x+5(4x+1)), so:We get rid of parentheses
3x+5(4x+1)
We multiply parentheses
3x+20x+5
We add all the numbers together, and all the variables
23x+5
Back to the equation:
-(23x+5)
-23x-5+120=0
We add all the numbers together, and all the variables
-23x+115=0
We move all terms containing x to the left, all other terms to the right
-23x=-115
x=-115/-23
x=+5
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