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2x^2+4x-1920=0
a = 2; b = 4; c = -1920;
Δ = b2-4ac
Δ = 42-4·2·(-1920)
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15376}=124$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-124}{2*2}=\frac{-128}{4} =-32 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+124}{2*2}=\frac{120}{4} =30 $
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